3t^2-275t=0

Solution for 3t^2-275t=0 equation:

3t^2-275t=0

a = 3; b = -275; c = 0;
Δ = b2-4ac
Δ = -2752-4·3·0
Δ = 75625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{75625}=275$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-275)-275}{2*3}=\frac{0}{6}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-275)+275}{2*3}=\frac{550}{6}
=91+2/3
$